100x^2+10x=120

Solution for 100x^2+10x=120 equation:

100x^2+10x=120

We move all terms to the left:

100x^2+10x-(120)=0

a = 100; b = 10; c = -120;
Δ = b2-4ac
Δ = 102-4·100·(-120)
Δ = 48100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48100}=\sqrt{100*481}=\sqrt{100}*\sqrt{481}=10\sqrt{481}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{481}}{2*100}=\frac{-10-10\sqrt{481}}{200}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{481}}{2*100}=\frac{-10+10\sqrt{481}}{200}
$